-7y^2-69y+10=0

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Solution for -7y^2-69y+10=0 equation:



-7y^2-69y+10=0
a = -7; b = -69; c = +10;
Δ = b2-4ac
Δ = -692-4·(-7)·10
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-71}{2*-7}=\frac{-2}{-14} =1/7 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+71}{2*-7}=\frac{140}{-14} =-10 $

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